document.write( "Question 800849: A parabola has vertex (0,0) and focus on the y axis
\n" ); document.write( "a) find the equation of the parabola if it passes through the point (4,12)\r
\n" ); document.write( "\n" ); document.write( "Can you please help me out, thanks so much in advance:)
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Algebra.Com's Answer #483295 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
Since your parabola has its turning point at the origin, (0,0), and focus on y axis the equation is
\n" ); document.write( "(1)\"+y+=+a%2Ax%5E2+%2B0+%2B0+\"
\n" ); document.write( "I include the two zeroes in the equations to indicate that the y-intercept is zero and the axis of symmetry is at x equals zero.
\n" ); document.write( "Since the parabola passes through the point (4,12) we have
\n" ); document.write( "(2) 12 = a*4^2 or
\n" ); document.write( "(3) 12 = 16a or
\n" ); document.write( "(4) a = 12/16 or
\n" ); document.write( "(5) a = 3/4
\n" ); document.write( "Let's check this.
\n" ); document.write( "Is (12 = 3/4*4^2)?
\n" ); document.write( "Is (12 = 3/4*16)?
\n" ); document.write( "Is (12 = 3*4)?
\n" ); document.write( "Is (12 = 12)? Yes
\n" ); document.write( "Answer: The equation of the parabola that meets the conditions stated is \"y+=+%283%2F4%29x%5E2\"
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