document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=800817>Question 800817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 100ft its length is five more than twice the width find the dimensions of the rectangle.   i know you have to set up two equations and  substitute or eliminate but i don't know how to start <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483275 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w = width<BR>\n" );
document.write( "2w + 5 = length {length is 5 more than twice width}\r<BR>\n" );
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document.write( "Perimeter of a rectangle is 2(width) + 2(length)\r<BR>\n" );
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document.write( "2w + 2(2w + 5) = 100  {substituted width and length into perimeter formula}<BR>\n" );
document.write( "2w + 4w + 10 = 100 {used distributive property}<BR>\n" );
document.write( "6w + 10 = 100 {combined like terms}<BR>\n" );
document.write( "6w = 90 {subtracted 10 from each side}<BR>\n" );
document.write( "w = 15 {divided each side by 6}<BR>\n" );
document.write( "2w + 5 = 35 {substituted 15, in for w, into 2w + 5}\r<BR>\n" );
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document.write( "width is 15 ft<BR>\n" );
document.write( "length is 35 ft<BR>\n" );
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