document.write( "Question 800759: jack was 11 years older than priscilla together their ages are 153, what were their ages.\r
\n" ); document.write( "\n" ); document.write( "Please help me break this down in the correct formula having lots of trouble understanding. \n" ); document.write( "
Algebra.Com's Answer #483273 by VictoryStar(6)\"\" \"About 
You can put this solution on YOUR website!
Use Priscilla's age as X, as we do not know.
\n" ); document.write( "Since Jack is eleven years older, that adds 11 to her age, which is X + 11
\n" ); document.write( "Since their ages equal to 153, on the right side of the equation, it would = 153
\n" ); document.write( "Combine these three, and you will get X + X + 11 = 153.
\n" ); document.write( "Subtract 11 from both sides, and you will have X + X = 142
\n" ); document.write( "Combine like terms (Where all numbers that have a similar ending are added together) and you get 2X = 142
\n" ); document.write( "Divide both sides by two, so you can isolate the variable (Getting the X on it's own.)
\n" ); document.write( "X = 71
\n" ); document.write( "Priscilla's age is 71, and since Jack is 11 years older (X + 11 = 71 + 11),
\n" ); document.write( "You will get 82.
\n" ); document.write( "Plug in 71 for X, to check your work.
\n" ); document.write( "X + X + 11 = 153
\n" ); document.write( "2x + 11 = 153
\n" ); document.write( "2 (71) + 11 = 153
\n" ); document.write( "Therefore, our answers are correct.
\n" ); document.write( " \n" ); document.write( "
\n" );