document.write( "Question 800505: Please help me solve this percentage question: To arrive on time a bus needs 18 hours to complete a normal trip. If the bus must arrive in 10 hours, by what percent must the speed of the bus be increased ? Kindly show the steps. \n" ); document.write( "
Algebra.Com's Answer #483251 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! To arrive on time a bus needs 18 hours to complete a normal trip. \n" ); document.write( " If the bus must arrive in 10 hours, by what percent must the speed of the bus be increased ? \n" ); document.write( ": \n" ); document.write( "Let s = the normal speed of the bus \n" ); document.write( "let x = per cent increase in decimal form (for example 1.20 is a 20% increase) \n" ); document.write( ": \n" ); document.write( "distance = 18s (time*speed) \n" ); document.write( "the same distance can be written \n" ); document.write( "dist = 10xs \n" ); document.write( "therefore \n" ); document.write( "10xs = 18s \n" ); document.write( "divide both sides by 10s \n" ); document.write( "x = 1.8, the normal speed has to multiplied by 1.8 \n" ); document.write( "That's a 80% increase in speed to make the trip in 10 hrs \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can confirm this say, normal speed is 50 mph \n" ); document.write( "then dist: \n" ); document.write( " 18*50 = 900 mi \n" ); document.write( "increase the speed by 80%: 1.8 * 50 = 90 mph \n" ); document.write( " 10*90 = 900 mi \n" ); document.write( " |