document.write( "Question 800728: Maria drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 9 hours. When Maria drove home, there was no traffic and the trip only took 4 hours. If her average rate was 40 miles per hour faster on the trip home, how far away does Maria live from the mountains?\r
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document.write( "Do not do any rounding.\r
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Algebra.Com's Answer #483225 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let Maria live x miles from the mountains\r \n" ); document.write( "\n" ); document.write( "Let her rate to mountains be y\r \n" ); document.write( "\n" ); document.write( "t=d/r\r \n" ); document.write( "\n" ); document.write( "x/y = 9 \n" ); document.write( "x=9y\r \n" ); document.write( "\n" ); document.write( "Return trip 4 hours \n" ); document.write( "rate = y+40\r \n" ); document.write( "\n" ); document.write( "x/(y+40) =4\r \n" ); document.write( "\n" ); document.write( "substitute x \n" ); document.write( "9y/(y+40)=4\r \n" ); document.write( "\n" ); document.write( "9y=4y+160\r \n" ); document.write( "\n" ); document.write( "9y-4y=160 \n" ); document.write( "5y=160 \n" ); document.write( "y= 160/5 \n" ); document.write( "y=32\r \n" ); document.write( "\n" ); document.write( "x=9y \n" ); document.write( "x=9*32= 288 miles\r \n" ); document.write( "\n" ); document.write( "distance to the mountain = 288 miles \n" ); document.write( " |