document.write( "Question 800702: if a rectangles perimetermis 54cm and the length is twice the width. What is the area \n" ); document.write( "
Algebra.Com's Answer #483208 by Cromlix(4381)\"\" \"About 
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Width = x
\n" ); document.write( "Length = 2x
\n" ); document.write( "Perimeter = 2*width + 2*length
\n" ); document.write( "54 = 2*x + 2*2x
\n" ); document.write( "54 = 2x + 4x
\n" ); document.write( "6x = 54
\n" ); document.write( "x = 9cm
\n" ); document.write( "Width = 9 cm
\n" ); document.write( "Length = 18 cm
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-) \n" ); document.write( "
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