document.write( "Question 800652: how many gallons of 15 percent saw solution must be mixed with 30 gallons of 25 percent solution to obtain 20 percent solution \n" ); document.write( "
Algebra.Com's Answer #483207 by mananth(16946)![]() ![]() You can put this solution on YOUR website! --- percent ---------------- Amount \n" ); document.write( "Solution I 25 ---------------- 30 gallons \n" ); document.write( "solution II 15 ---------------- x gallons \n" ); document.write( "Mixture 20 ---------------- 30 + x gallons \n" ); document.write( " \n" ); document.write( "25 * 30 + 15 x = 20 ( 30 + x ) \n" ); document.write( "750 + 15 x = 600 + 20 x \n" ); document.write( "15 x -20 x = -750 + 600 \n" ); document.write( "-5 x = -150 \n" ); document.write( "/ -5 \n" ); document.write( "x = 30 gallons solution II \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |