document.write( "Question 8876: A woman is asked her weight. She, appropriately, replies (you should never ask a woman her weight – unless you are really asking for a slap in the face or a divorce) that she weighs 60 lbs plus half her weight.
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Algebra.Com's Answer #4832 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
The equation is based upon the fact that \"Her weight is equal to 60 lbs. plus half her weight.\"\r
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\n" ); document.write( "\n" ); document.write( "Srart by letting x = thw weight of the woman (if she is like most women I know, in this case, x is REALLY the unknown!)\r
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\n" ); document.write( "\n" ); document.write( "\"Her weight is equal to 60 lbs. plus half her weight.\"
\n" ); document.write( "\"+x+++++=++++60+%2B+%281%2F2%29%2A+x+\"\r
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\n" ); document.write( "\n" ); document.write( "You probably don't like that fraction, so just multiply both sides of the equation by 2 and get rid of it.
\n" ); document.write( "\"2x+=+120+%2B+2%2A%281%2F2%29%2Ax\"
\n" ); document.write( "\"2x+=+120+%2B+x\"\r
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\n" ); document.write( "\n" ); document.write( "Subtract x from each side, and you get:
\n" ); document.write( "\"2x+-+x+=+120+%2B+x+-+x\"
\n" ); document.write( "\"x+=+120\"\r
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\n" ); document.write( "\n" ); document.write( "Check it out: Her weight is 120, which equals 60 plus half of her weight, which is another 60.\r
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\n" ); document.write( "\n" ); document.write( "You might figure out a way to do this intuitively (like in your head), but I like equations. They are reliable!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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