document.write( "Question 8876: A woman is asked her weight. She, appropriately, replies (you should never ask a woman her weight – unless you are really asking for a slap in the face or a divorce) that she weighs 60 lbs plus half her weight.
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document.write( "What is her actual weight (in lbs)? \n" );
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Algebra.Com's Answer #4832 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! The equation is based upon the fact that \"Her weight is equal to 60 lbs. plus half her weight.\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Srart by letting x = thw weight of the woman (if she is like most women I know, in this case, x is REALLY the unknown!)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"Her weight is equal to 60 lbs. plus half her weight.\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You probably don't like that fraction, so just multiply both sides of the equation by 2 and get rid of it. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract x from each side, and you get: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check it out: Her weight is 120, which equals 60 plus half of her weight, which is another 60.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You might figure out a way to do this intuitively (like in your head), but I like equations. They are reliable!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " \n" ); document.write( " |