document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=799968>Question 799968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you rewrite these equations in Function Form: <BR>\n" );
document.write( "-3x+y=12<BR>\n" );
document.write( "2x+3y=6<BR>\n" );
document.write( "-x-y=5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483161 by </B><A HREF=/tutors/aboutme.mpl?userid=thepianist25><B>thepianist25(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thepianist25><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To write these equations in function form, first change them to slope-intercept form.  \r<BR>\n" );
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document.write( "Slope intercept form is \"y = mx + b\", where m is the slope of a line, x and y are the coordinates, and b is the y-intercept. Once you have solved for y, then you can can simply substitute \"f(x)\" in place of y, to show that it is in function form (which you could graph).\r<BR>\n" );
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document.write( "So, in -3x + y = 12, I must solve for \"y\".\r<BR>\n" );
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document.write( "-3x + y = 12<BR>\n" );
document.write( "-3x + 3x + y = 12 + 3x (addition axiom)<BR>\n" );
document.write( "y = 3x + 12\r<BR>\n" );
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document.write( "Notice that we are in slope-intercept form.  You can now change the equation to f(x) = 3x + 12\r<BR>\n" );
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document.write( "The other two equations are done the same way.\r<BR>\n" );
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document.write( "2x + 3y = 6<BR>\n" );
document.write( "2x - 2x + 3y= 6 - 2x (subtraction axiom)<BR>\n" );
document.write( "3y = -2x + 6<BR>\n" );
document.write( "3y/3 = -2x/3 + 6/3 (division axiom)<BR>\n" );
document.write( "y = -2x/3 + 2 or f(x) = -2x/3 + 2\r<BR>\n" );
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document.write( "-x - y = 5<BR>\n" );
document.write( "-x + x - y = 5 + x (addition axiom)<BR>\n" );
document.write( "-y = x + 5 (At this point, I do not want to leave y with a negative on it. So if I divide both sides by -1, I will not destroy the equality of the equation.)\r<BR>\n" );
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document.write( "-y/-1 = x/-1 + 5/-1<BR>\n" );
document.write( "y = -x - 5 or f(x) = -x - 5 </SPAN>\n" );
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