document.write( "Question 800482: Please help me!! I do not understand how to do this question!\r
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document.write( "The equation of he circle is x^2 + y^2 = 6*x + 8*y -24 = 0. Find the equation of the diameter of the circle which passes through the point (-1,1).\r
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document.write( "Please help me!! I do not understand this question, how do I do it?!
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #483118 by mananth(16946)![]() ![]() You can put this solution on YOUR website! I am not too sure if you have typed correctly\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " x^2 + y^2 + 6*x + 8*y -24 = 0\r \n" ); document.write( "\n" ); document.write( "x^2-6x +y^2+8y -24=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2-6x+9 +y^2+8y+16=24+9+16\r \n" ); document.write( "\n" ); document.write( "(x+3)^2+(y+4)^2=49\r \n" ); document.write( "\n" ); document.write( "center =(3,-4)\r \n" ); document.write( "\n" ); document.write( "The other point is (-1,1)\r \n" ); document.write( "\n" ); document.write( "Find the equation of line passing through (-1,1) and (3,-4)\r \n" ); document.write( "\n" ); document.write( "(y-1)/(1+4) =(x-(-1))/(-1-3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(y-1)/5 =(x+1)/-4\r \n" ); document.write( "\n" ); document.write( "-4(y-1)=5(x+1) \n" ); document.write( "-4y+4=5x+5 \n" ); document.write( "5x+4y+1=0 \n" ); document.write( " \n" ); document.write( " |