document.write( "Question 800161: Josie leaves home on her bicycle and rides out to the edge of the forest for three hours. on her return trip, along the same route, it takes her three-quarters of an hour longer. if her rate on the trip was two miles per hour slower than on the trip out forest, then
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document.write( "A) find the rate to bicycle INTO the forest?
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document.write( "B) what is the one-way distance from home to the forest? \n" );
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Algebra.Com's Answer #483116 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Josie leaves home on her bicycle and rides out to the edge of the forest for three hours. \n" ); document.write( " on her return trip, along the same route, it takes her three-quarters of an hour longer. \n" ); document.write( " if her rate on the trip was two miles per hour slower than on the trip out forest, then \n" ); document.write( ": \n" ); document.write( "A) find the rate to bicycle INTO the forest? \n" ); document.write( "let s = speed into the forest \n" ); document.write( "then \n" ); document.write( "(s-2) = speed returning \n" ); document.write( "Write a distance equation, dist = time * speed \n" ); document.write( ": \n" ); document.write( "dist back = dist in \n" ); document.write( "3.75((s-2) = 3s \n" ); document.write( "3.75s - 7.5 = 3s \n" ); document.write( "3.75s - 3 = 7.5 \n" ); document.write( ".75s = 7.5 \n" ); document.write( "s = 7.5/.75 \n" ); document.write( "s = 10 mph into the forest \n" ); document.write( ": \n" ); document.write( "B) what is the one-way distance from home to the forest? \n" ); document.write( "dist = speed * time \n" ); document.write( "d = 10 * 3 \n" ); document.write( "d = 30 miles \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions using return trip \n" ); document.write( "8 * 3.75 = 30 \n" ); document.write( " |