document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=800474>Question 800474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat leaves X and travels east for 10km. It then sails 10km south to Y. Find the distance and bearing from X from Y  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483094 by </B><A HREF=/tutors/aboutme.mpl?userid=meraj><B>meraj(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=meraj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483094\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the distance XY=10km be the base of the triangle and distance <BR>\n" );
document.write( "YZ=10km be another base of the triangle.<BR>\n" );
document.write( "Now,<BR>\n" );
document.write( "XZ^2=XY^2+YZ^2<BR>\n" );
document.write( "XZ^2=10^2+10^2<BR>\n" );
document.write( "XZ^2=100+100<BR>\n" );
document.write( "XZ^2=200<BR>\n" );
document.write( "XZ=14.14213562373095km<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );