document.write( "Question 800479: Please help me!!\r
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document.write( "Find the equation of the circle passing through the point (-1,1) and having the centre on the point of intersection of the lines x + 3y + 7 = 0 and 3*x - 2*y -12 = 0.\r
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document.write( "Please help me!! Thanks! \n" );
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Algebra.Com's Answer #483091 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Find the center of the circle by solving for x & y \r \n" ); document.write( "\n" ); document.write( "1 x + 3 y = -7 .............1 \n" ); document.write( "Total value \n" ); document.write( "3 x -2 y = 12 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by 2 \n" ); document.write( "Multiply (2) by 3 \n" ); document.write( "2 x 6 y = -14 \n" ); document.write( "9 x -6 y = 36 \n" ); document.write( "Add the two equations \n" ); document.write( "11 x = 22 \n" ); document.write( "/ 11 \n" ); document.write( "x = 2 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1 x + 3 y = -7 \n" ); document.write( "2 + 3 y = -7 \n" ); document.write( " 3 y = -7 -2 \n" ); document.write( " 3 y = -9 \n" ); document.write( " y = -3 \n" ); document.write( "center (2,-3) \r \n" ); document.write( "\n" ); document.write( "point(-1,1)\r \n" ); document.write( "\n" ); document.write( "Frame the equation \n" ); document.write( " |