document.write( "Question 800452: find the equation of the circle with center on x+y=4 and 5x+2y+1=0, and whose radius is 3 \n" ); document.write( "
Algebra.Com's Answer #483066 by lwsshak3(11628)\"\" \"About 
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find the equation of the circle with center on x+y=4 and 5x+2y+1=0, and whose radius is 3
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\n" ); document.write( "x+y=4
\n" ); document.write( "y=4-x
\n" ); document.write( "..
\n" ); document.write( "5x+2y+1=0
\n" ); document.write( "plug in (4-x) for y
\n" ); document.write( "5x+2(4-x)+1=0
\n" ); document.write( "5x+8-2x+1=0
\n" ); document.write( "3x+9=0
\n" ); document.write( "3x=-9
\n" ); document.write( "x=-3
\n" ); document.write( "y=4-x=4-(-3)=7
\n" ); document.write( "(-3,7)(point of intersection for given two lines)=coordinates of center of circle
\n" ); document.write( "Equation of circle: (x+3)^2+(y-7)^2=9
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