document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=800405>Question 800405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What quantity of 80 per cent acid solution must be mixed with a 20 per cent solution to produce 120 mL of a 50 per cent solution?\r<BR>\n" );
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document.write( "-Please explain the steps also, not just the answer. So I can understand it better :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483059 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What quantity of 80 per cent acid solution must be mixed with a 20 per cent solution to produce 120 mL of a 50 per cent solution? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
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document.write( "0.80x + 0.20(120-x) = 0.50*120<BR>\n" );
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document.write( "80x + 20*120 - 20x = 50*120<BR>\n" );
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document.write( "60x = 30*120<BR>\n" );
document.write( "x = 60 mL (amt. of 80% solution needed)<BR>\n" );
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document.write( "120-60 = 60 mL (amt. of 20% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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