document.write( "Question 800405: What quantity of 80 per cent acid solution must be mixed with a 20 per cent solution to produce 120 mL of a 50 per cent solution?\r
\n" ); document.write( "\n" ); document.write( "-Please explain the steps also, not just the answer. So I can understand it better :)
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Algebra.Com's Answer #483058 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+a+\" = ml of 80% solution needed
\n" ); document.write( "\"+.8a+\" = ml of acid in 80% solution
\n" ); document.write( "Let \"+b+\" = ml of 20% solution needed
\n" ); document.write( "\"+.2b+\" = ml of acid in 20% solution
\n" ); document.write( "----------------------------------
\n" ); document.write( "(1) \"+a+%2B+b+=+120+\"
\n" ); document.write( "(2) \"+%28+.8a+%2B+.2b+%29+%2F+120+=+.5+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "(2) \"+.8a+%2B+.2b+=+.5%2A120+\"
\n" ); document.write( "(2) \"+.8a+%2B+.2b+=+60+\"
\n" ); document.write( "(2) \"+8a+%2B+2b+=+600+\"
\n" ); document.write( "(2) \"+4a+%2B+b+=+300+\"
\n" ); document.write( "Subtract (1) from (2)
\n" ); document.write( "(2) \"+4a+%2B+b+=+300+\"
\n" ); document.write( "(1) \"+-a+-+b+=+-120+\"
\n" ); document.write( "\"+3a+=+180+\"
\n" ); document.write( "\"+a+=+60+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+a+%2B+b+=+120+\"
\n" ); document.write( "(1) \"+b+=+60+\"
\n" ); document.write( "60 ml of 80% acid solution are needed
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+.8%2A60+%2B+.2%2A60+%29+%2F+120+=+.5+\"
\n" ); document.write( "(2) \"+%28+48+%2B+12+%29+%2F+120+=+.5+\"
\n" ); document.write( "(2) \"+60+=+.5%2A120+\"
\n" ); document.write( "(2) \"+60+=+60+\"
\n" ); document.write( "OK\r
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