document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=800410>Question 800410</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can't figure this problem out. I got -4077 and the book said it was -45<BR>\n" );
document.write( "i don't know what I'm doing wrong please help!! (:\r<BR>\n" );
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document.write( "P(y)=8y3-12y-5<BR>\n" );
document.write( "Find P(-2) and P(1/3)\r<BR>\n" );
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document.write( "ps the three is 3 cubed \r<BR>\n" );
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document.write( "thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483055 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483055\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(y)=8y3-12y-5\r<BR>\n" );
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document.write( "P(-2) = 8*(-2)^3-12*(-2)-5\r<BR>\n" );
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document.write( "=8*-8+24-5<BR>\n" );
document.write( "=-45\r<BR>\n" );
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document.write( "Find P(-2) and P(1/3)\r<BR>\n" );
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document.write( "P(y)=8y3-12y-5<BR>\n" );
document.write( "=8(1/3)^3 -12(1/3)-5\r<BR>\n" );
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document.write( "=8/27 -4-5<BR>\n" );
document.write( "=8/27 -9<BR>\n" );
document.write( "=-235/27 </SPAN>\n" );
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