document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=800372>Question 800372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I didn't know what category to put this in...<BR>\n" );
document.write( "Solve for 4+8+12+...+204+208 is there a simpler way to do this than adding every number between the beginning and end?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483051 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> its arithmetic progression\r<BR>\n" );
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document.write( "The nth term is given by<BR>\n" );
document.write( "Tn = a+(n-1)d\r<BR>\n" );
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document.write( "a= first term<BR>\n" );
document.write( "d= difference between terms<BR>\n" );
document.write( "n = number of terms\r<BR>\n" );
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document.write( "208=4+(n-1)4\r<BR>\n" );
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document.write( "208=4+4n-4<BR>\n" );
document.write( "208=4n<BR>\n" );
document.write( "n=52\r<BR>\n" );
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document.write( "Sum of n terms <BR>\n" );
document.write( "Sn = n/2(2a+(n-1)d)\r<BR>\n" );
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document.write( "Sn = 52/2(2*4+(51*4)\r<BR>\n" );
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document.write( "=27(8+204)<BR>\n" );
document.write( "=27*212<BR>\n" );
document.write( "=5724\r<BR>\n" );
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document.write( "208=4(n-1)4 </SPAN>\n" );
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