document.write( "Question 67909: 3log2 x=1+log2 32 \n" ); document.write( "

Algebra.Com's Answer #48304 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
3log2 x=1+log2 32
\n" ); document.write( "---------
\n" ); document.write( "log(base2)x^3 = 1+log(base2)32
\n" ); document.write( "log(base2)[x^3/32] = 1
\n" ); document.write( "x^3/32 = 2^1
\n" ); document.write( "x^3=64
\n" ); document.write( "x=4
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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