document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1396>Question 1396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Container A has a total volume of exactly 3/4 quart. Container B can hold exactly 4/7 of a quart less than 6 quarts. What fraction of container B must be filled in order to hold the same volume as Container A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #483 by </B><A HREF=/tutors/aboutme.mpl?userid=abhinav75><B>abhinav75(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=abhinav75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> capacity of container A = 3/4 quarts<BR>\n" );
document.write( "capacity of container B = 6 - 4/7 = (6*7 - 4)/7 = 38/7 quarts\r<BR>\n" );
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document.write( "the required fraction is (3/4)/(38/7)<BR>\n" );
document.write( "= (3*7)/(38*4)<BR>\n" );
document.write( "= 21/152\r<BR>\n" );
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document.write( "the fraction is 21/152 </SPAN>\n" );
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