document.write( "Question 800186: the perimeter of a rectangle is 85ft. the length of the rectangle is 4ft more than its width. what is the equation used to find the width? \n" ); document.write( "
Algebra.Com's Answer #482978 by waynest(281)![]() ![]() ![]() You can put this solution on YOUR website! p = 85 \n" ); document.write( "length (L) = w + 4 \n" ); document.write( "width = w\r \n" ); document.write( "\n" ); document.write( "p = 2w + 2L\r \n" ); document.write( "\n" ); document.write( "85 = 2w 2(w + 4) \n" ); document.write( "85 = 2w + 2w + 8 \n" ); document.write( "85 = 4w + 8 \n" ); document.write( "85 - 8 = 4w \n" ); document.write( "77 = 4w \n" ); document.write( "77/4 = 4w/4 \n" ); document.write( "19.25 = w\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "2(19.25) + 2(19.25 + 4) = 85 \n" ); document.write( "38.5 + 2(23.25) = 85 \n" ); document.write( "38.5 + 46.5 = 85 \n" ); document.write( "85 = 85 \n" ); document.write( " |