document.write( "Question 800086: how to find a third degree polynomial function that f(-1)=3 and whose zeros are:1,2,and 3 ? \n" ); document.write( "

Algebra.Com's Answer #482913 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"f%28x%29=k%28x-1%29%28x-2%29%28x-3%29\"$ , using the zeros but not knowing the possible factor on the entire function.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Using the known other point, $\"k%28-1-1%29%28-1-2%29%28-1-3%29=3\"$
\n" ); document.write( " $\"k%28-2%29%28-3%29%28-4%29=3\"$
\n" ); document.write( " $\"-24k=3\"$
\n" ); document.write( " $\"k=-1%2F8\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"highlight%28f%28x%29=-%281%2F8%29%28x-1%29%28x-2%29%28x-3%29%29\"$
\n" ); document.write( "You can multiply and simplify if you want f in general form. \n" ); document.write( "

\n" );