document.write( "Question 799889: You've just opened your piggy bank to discover 55 coins totaling $10.00. If there are more nickles than pennies, more dimes than nickles and more quarters than dimes, how many of each coin do you have?
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Algebra.Com's Answer #482865 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! In order of the most to the least, you have: \n" ); document.write( "Q \n" ); document.write( "D \n" ); document.write( "N \n" ); document.write( "P \n" ); document.write( "You can have 5 pennies or 10 pennies \n" ); document.write( "Suppose \n" ); document.write( "Q = ? \n" ); document.write( "D = 1 \n" ); document.write( "N = 1 \n" ); document.write( "P = 5 \n" ); document.write( "------- \n" ); document.write( "Now I need to put the amounts in descending order \n" ); document.write( "Q = ? \n" ); document.write( "D = 7 \n" ); document.write( "N = 6 \n" ); document.write( "P = 5 \n" ); document.write( "D + N + P = 18 and that amount is $1.05 \n" ); document.write( "Add 2 more dimes, and I get $1.25, or 5 quarters \n" ); document.write( "Now I have: \n" ); document.write( "Q = 1000/25 - 5 = 35 \n" ); document.write( "D = 9 \n" ); document.write( "N = 6 \n" ); document.write( "P = 5 \n" ); document.write( "-------- \n" ); document.write( "Total coins is 55, and \n" ); document.write( "P*1 = 5 \n" ); document.write( "N*5 = 30 \n" ); document.write( "D*10 = 90 \n" ); document.write( "Q*35 = 875 \n" ); document.write( "----------- \n" ); document.write( "1000 cents total or $10.00 \n" ); document.write( "Hope this makes sense\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |