document.write( "Question 799691: Ed can do a job in 4 days. When Ed and Maymay work together, it would take them 2 1/3 days. How long would the job take Maymay to do the job alone? \n" ); document.write( "
Algebra.Com's Answer #482847 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Ed can do a job in 4 days.
\n" ); document.write( " When Ed and Maymay work together, it would take them 2 1/3 days.
\n" ); document.write( " How long would the job take Maymay to do the job alone?
\n" ); document.write( ":
\n" ); document.write( "Let m = May^2 time to do the job alone
\n" ); document.write( "let the completed job = 1
\n" ); document.write( "Change 2 1/3 days to 7/3
\n" ); document.write( ":
\n" ); document.write( "A shared work equation
\n" ); document.write( "\"%287%2F3%29%2F4\" + \"%287%2F3%29%2Fm\" = 1
\n" ); document.write( "Which is
\n" ); document.write( "\"7%2F12\" + \"7%2F%283m%29+\" = 1
\n" ); document.write( "multiply by 12m, resulting in
\n" ); document.write( "7m + 4(7) = 12m
\n" ); document.write( "28 = 12m - 7m
\n" ); document.write( "28 = 5m
\n" ); document.write( "m = 28/5
\n" ); document.write( "m = 5\"3%2F5\" days May^2 alone
\n" ); document.write( "
\n" ); document.write( "
\n" );