document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=799736>Question 799736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. A piece of wire of w cm long is bent to form a rectangle. The length of the rectangle is x cm, and its area is 21 cm2.<BR>\n" );
document.write( "a. Show that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=++w=2x%2B++42%2Fx++ ALIGN=MIDDLE  ALT=\"++w=2x%2B++42%2Fx++\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "b. Given that the perimeter of the rectangle is 19 cm, find the breadth of the rectangle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482782 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Area:  <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE A\ =\ xy\">\r<BR>\n" );
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document.write( "Perimeter:  <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE P\ =\ 2x\ +\ 2y\">\r<BR>\n" );
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document.write( "Since you are given that A = 21, it must be true that <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE y\ =\ \frac{21}{x}\">.  You are also given that the perimeter is <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE w\">.\r<BR>\n" );
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document.write( "Substituting in the perimeter expression:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ w\ =\ 2x\ +\ 2\left(\frac{21}{x}\right)\ =\ 2x\ +\ \frac{42}{x}\">\r<BR>\n" );
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document.write( "If <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE w\ =\ 19\">, then solve <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE 2x\ +\ \frac{42}{x}\ =\ 19\"> for <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE x\">.  Note:  \"Breadth\" is generally taken to mean \"width\" which is, in turn, generally taken to mean the smaller of the two dimensions of a rectangle.  The two solutions of the quadratic equation that results from the perimeter equation are the length and width of the rectangle and you should report the smaller of the two.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "<font face=\"Math1\" size=\"+2\">Egw to Beta kai to Sigma</font><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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