document.write( "Question 799704: A lab technician has 40% alcohol solution and 60% alcohol solution. He need to make 100 ml. solution that is 48% alcohol. How much of each available solution should he use ? \n" ); document.write( "
Algebra.Com's Answer #482759 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Solution I 40.00% ---------------- x ml
\n" ); document.write( "solution II 60.00% ------ 100 - x ml
\n" ); document.write( "Mixture 48.00% ---------------- 100
\n" ); document.write( "Total 100 ml
\n" ); document.write( "40.00% x + 60.00% ( 100 - x ) = 48.00% * 100
\n" ); document.write( "40 x + 60 ( 100 - x ) = 4800
\n" ); document.write( "40 x + 6000 - 60 x = 4800
\n" ); document.write( "40 x - 60 x = 4800 - -6000
\n" ); document.write( "-20 x = -1200
\n" ); document.write( "/ -20
\n" ); document.write( " x = 60 ml 40.00% Solution I
\n" ); document.write( " 40 ml 60.00% solution II
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\n" ); document.write( "m.ananth@hotmail.ca
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