document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=799415>Question 799415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation in the form of y=mx+b through (2,2), perpendicular to y=3x+4. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482747 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation in the form of y=mx+b through (2,2), perpendicular to y=3x+4.<BR>\n" );
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document.write( "Equation of a line: y=mx+b, m=slope, b=y-intercept<BR>\n" );
document.write( "given equation:y=3x+4<BR>\n" );
document.write( "slope,m=3<BR>\n" );
document.write( "slope of line perpendicular to given line=-1/3(negative recprocal)<BR>\n" );
document.write( "Equation:y=-x/3+b<BR>\n" );
document.write( "solve for b using coordinates of given point(2,2)<BR>\n" );
document.write( "2=-2/3+b<BR>\n" );
document.write( "b=2+2/3=8/3<BR>\n" );
document.write( "equation of perpendicular line:<BR>\n" );
document.write( "y=-x/3+8/3 </SPAN>\n" );
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