document.write( "Question 67890: Hi, I need help solving this problem. I have a big! problem with mixture problems : and I have to take chemistry soon. Please help!! Thanks
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\n" ); document.write( "A radiator contains 6L of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 50% antifreeze solution?
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Algebra.Com's Answer #48274 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A radiator contains 6L of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 50% antifreeze solution?
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\n" ); document.write( "Amt of 25% solution = 6 liters; amt of active ingredient= 0.25*6= 1.5 liters
\n" ); document.write( "Amt of 25% removed is x liters; amt of active ingre removed is 0.25x liters
\n" ); document.write( "Amt replaced is x liters; amt of active ingredient added = x liters
\n" ); document.write( "Resulting amount is 6 liters ; amt of active ingredient = 0.50(6)= 3 liters
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\n" ); document.write( "EQUATION:
\n" ); document.write( "active -active + active = active
\n" ); document.write( "1.5 - 0.25x + x = 3
\n" ); document.write( "0.75x=1.5
\n" ); document.write( "x=2 liters
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\n" ); document.write( "2 liters of the 25% solution should be drained out and replaced
\n" ); document.write( "with 2 liters of 100% antifreeze.
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\n" ); document.write( "Cheers
\n" ); document.write( "Stan H.
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