document.write( "Question 67890: Hi, I need help solving this problem. I have a big! problem with mixture problems : and I have to take chemistry soon. Please help!! Thanks
\n" );
document.write( "Question:
\n" );
document.write( "A radiator contains 6L of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 50% antifreeze solution? \n" );
document.write( "
Algebra.Com's Answer #48274 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A radiator contains 6L of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 50% antifreeze solution? \n" ); document.write( "---------------- \n" ); document.write( "Amt of 25% solution = 6 liters; amt of active ingredient= 0.25*6= 1.5 liters \n" ); document.write( "Amt of 25% removed is x liters; amt of active ingre removed is 0.25x liters \n" ); document.write( "Amt replaced is x liters; amt of active ingredient added = x liters \n" ); document.write( "Resulting amount is 6 liters ; amt of active ingredient = 0.50(6)= 3 liters \n" ); document.write( "---------------- \n" ); document.write( "EQUATION: \n" ); document.write( "active -active + active = active \n" ); document.write( "1.5 - 0.25x + x = 3 \n" ); document.write( "0.75x=1.5 \n" ); document.write( "x=2 liters \n" ); document.write( "----------------- \n" ); document.write( "2 liters of the 25% solution should be drained out and replaced \n" ); document.write( "with 2 liters of 100% antifreeze. \n" ); document.write( "--------- \n" ); document.write( "Cheers \n" ); document.write( "Stan H. \n" ); document.write( " |