document.write( "Question 799633: The sum of four times the first number and three times the second number is 15. The difference of three times the first number and twice the second number is 7. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #482737 by mananth(16946)\"\" \"About 
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let the numbers be x & y\r
\n" ); document.write( "\n" ); document.write( "4 x + 3 y = 15 .............1
\n" ); document.write( "
\n" ); document.write( "3 x -2 y = 7 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 2
\n" ); document.write( "Multiply (2) by 3
\n" ); document.write( "8 x 6 y = 30
\n" ); document.write( "9 x -6 y = 21
\n" ); document.write( "Add the two equations
\n" ); document.write( "17 x = 51
\n" ); document.write( "/ 17
\n" ); document.write( "x = 3
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "4 x + 3 y = 15
\n" ); document.write( "12 + 3 y = 15
\n" ); document.write( " 3 y = 15 -12
\n" ); document.write( " 3 y = 3
\n" ); document.write( " y = 1
\n" ); document.write( "x= 3
\n" ); document.write( "y= 1
\n" ); document.write( "m.ananth@hotmail.ca
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