document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=798996>Question 798996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an athletic field is twice as long as it is wide, if the perimeter of the field is 96 yards what are the dimensions?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482730 by </B><A HREF=/tutors/aboutme.mpl?userid=harpazo><B>harpazo(655)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=harpazo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=harpazo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2L + 2w\r<BR>\n" );
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document.write( "96 = 2x + 2x\r<BR>\n" );
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document.write( "96 = 4x\r<BR>\n" );
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document.write( "96/4 = x \r<BR>\n" );
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document.write( "24 = x\r<BR>\n" );
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document.write( "The width is 24 yards. The length is 48 yards. </SPAN>\n" );
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