document.write( "Question 799390: The base of a triangle is 2 inches more than 3 times the height. If the area is 8 square inches, find the base and the height \n" ); document.write( "
Algebra.Com's Answer #482643 by waynest(281)![]() ![]() ![]() You can put this solution on YOUR website! base = 3h + 2 \n" ); document.write( "height = h \n" ); document.write( "Area = 8\r \n" ); document.write( "\n" ); document.write( "h(3h + 2) = 8 \n" ); document.write( "3h^2 + 2h = 8 \n" ); document.write( "3h^2 + 2h - 8 = 8 - 8 \n" ); document.write( "3h^2 + 2h - 8 = 0 \n" ); document.write( "(3h - 4)(h + 2) = 0 \n" ); document.write( "3h - 4 = 0 \n" ); document.write( "3h - 4 + 4 = 4 \n" ); document.write( "3h = 4 \n" ); document.write( "3h/3 = 4/3 \n" ); document.write( "h = 4/3\r \n" ); document.write( "\n" ); document.write( "h + 2 = 0 \n" ); document.write( "h + 2 - 2 = -2 \n" ); document.write( "h = -2 \n" ); document.write( "you can not have a negative value so h = 4/3 is the right one\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "3(4/3)^2 + 2(4/3) = 8 \n" ); document.write( "3(16/9) + 8/3 = 8 \n" ); document.write( "16/3 = 8/3 = 8 \n" ); document.write( "24/3 = 8 \n" ); document.write( "8 = 8 \n" ); document.write( " |