document.write( "Question 799369: Find the exact solution 8^(x-1)=16^(x+3)\r
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document.write( "I keep getting 3 log(2^x-1)=4 log(2^x+3)
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document.write( "which I turn into a big string of :
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document.write( "3 log (2) + x log (2) - log (2) = 4 log (2) + x log (2) + 3 log (2)
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document.write( "Which I simplify to :
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document.write( "x log (2)= 5 log (2) + x log (2)
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document.write( "but that doesnt seem right, wont the x log (2)'s cancel out? \n" );
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Algebra.Com's Answer #482637 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You started off on the right foot, but you will have a much easier time of it if you take the base 2 log of both sides.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "But since \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "from which it follows:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |