document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=799301>Question 799301</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The rectangular playing area of a professional football field is 100 yards long. The perimeter of the playing area is 920 feet. The formula for the perimeter of a rectangle is P = 2l + 2w. What is the width of the playing area?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482585 by </B><A HREF=/tutors/aboutme.mpl?userid=thejackal><B>thejackal(72)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thejackal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thejackal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482585\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the playing area is 100 yards long. convert it to feet thus\r<BR>\n" );
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document.write( "                     300 feet<BR>\n" );
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document.write( "|...........................................| W<BR>\n" );
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document.write( "P = 920 feet = 2l + 2W = 2(300) + 2W = 600 + 2W<BR>\n" );
document.write( "(920 - 600)/2 = W </SPAN>\n" );
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