document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=799268>Question 799268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car leaves Canberra heading towards Sydney on the freeway at 5pm travelling at a constant speed of 80km/hr. forty-five minutes later a second car leaves in pursuit of the fist car travelling at a constant speed of 110 km/hr. When will the second car catch up to the second car? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482577 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A car leaves Canberra heading towards Sydney on the freeway at 5pm travelling at a constant speed of 80km/hr. forty-five minutes later a second car leaves in pursuit of the fist car travelling at a constant speed of 110 km/hr. When will the second car catch up to the second car?\r<BR>\n" );
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document.write( "let second car take x hours to catch up<BR>\n" );
document.write( "speed = 110 km/h\r<BR>\n" );
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document.write( "distance = 110 x\r<BR>\n" );
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document.write( "First car\r<BR>\n" );
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document.write( "speed = 80 km/h<BR>\n" );
document.write( "time = x+3/4 hour\r<BR>\n" );
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document.write( "Distance = 80(x+ 3/4)\r<BR>\n" );
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document.write( "110x= 80(x+3/4)\r<BR>\n" );
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document.write( "11/8 x = x+3/4\r<BR>\n" );
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document.write( "11/8 x -x= 3/4\r<BR>\n" );
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document.write( "3x/8 = 3/4\r<BR>\n" );
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document.write( "3x=6<BR>\n" );
document.write( "x=2 hours\r<BR>\n" );
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document.write( "5.45+2 hours\r<BR>\n" );
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document.write( "7.45 pm\r<BR>\n" );
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document.write( " </SPAN>\n" );
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