document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=799258>Question 799258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i find the width of a rectangle when the perimeter is 280 feet and the length is 20 feet less than 3 times the width?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482574 by </B><A HREF=/tutors/aboutme.mpl?userid=Finavon><B>Finavon(81)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Finavon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let sides be l and b<BR>\n" );
document.write( "perimeter = 2*(l+b)<BR>\n" );
document.write( "l=3b-20<BR>\n" );
document.write( "substituting for l<BR>\n" );
document.write( "perimeter= 2*(3b-20+b) = 6b-40+2b = 8b-40<BR>\n" );
document.write( "280=8b-40 so 320=8b<BR>\n" );
document.write( "b=40<BR>\n" );
document.write( "l=120-20=100<BR>\n" );
document.write( "rectangle is 40cm by 100cm<BR>\n" );
document.write( "Check: perimeter=40+40+100+100=280<BR>\n" );
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