document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=799239>Question 799239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lenght of a rectangular floor is 8 feet greater that its width . If each dimension is Increased by two Feet, The Area  Is increased by  60 feet^2 . Find the dimensions of the floor. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482565 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482565\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width =x\r<BR>\n" );
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document.write( "length = (x+8)\r<BR>\n" );
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document.write( "Original area = x(x+8) sq.ft\r<BR>\n" );
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document.write( "Increase the dimensions by 2 feet\r<BR>\n" );
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document.write( "width = (x+2)\r<BR>\n" );
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document.write( "length = (x+10)\r<BR>\n" );
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document.write( "Area = (x+2)(x+10)\r<BR>\n" );
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document.write( "(x+2)(x+10)-x(x+2)=60 \r<BR>\n" );
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document.write( "(x+2)(x+10-x)=60\r<BR>\n" );
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document.write( "10(x+2)=60<BR>\n" );
document.write( "10x+20=60<BR>\n" );
document.write( "10x=40<BR>\n" );
document.write( "x=4\r<BR>\n" );
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document.write( "width = 4 and length = 4+8 =12 feet\r<BR>\n" );
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