document.write( "Question 799169: One bus left the city at 2:00PM and averaged 75 km/h. Another bus, traveling in the opposite direction, left the city at 5:00PM and averaged 85 km/h. At what time were the buses 705 km apart? \n" ); document.write( "
Algebra.Com's Answer #482563 by mananth(16946)![]() ![]() You can put this solution on YOUR website! One bus left the city at 2:00PM and averaged 75 km/h. Another bus, traveling in the opposite direction, left the city at 5:00PM and averaged 85 km/h. At what time were the buses 705 km apart?\r \n" ); document.write( "\n" ); document.write( "time difference between Bus I and Bus II = 3 hours\r \n" ); document.write( "\n" ); document.write( "Bus I travels 75*3 = 225 kmin 3 hours\r \n" ); document.write( "\n" ); document.write( "Total distance = 705\r \n" ); document.write( "\n" ); document.write( "difference = 705-225=480\r \n" ); document.write( "\n" ); document.write( "they are travelling in opposite directions\r \n" ); document.write( "\n" ); document.write( "so add speeds 75+85=160 km/h\r \n" ); document.write( "\n" ); document.write( "t= d/r\r \n" ); document.write( "\n" ); document.write( "t=480/160 = 3 hours\r \n" ); document.write( "\n" ); document.write( "Bus II starts at 5.00 pm \n" ); document.write( "so they will be 705 km away at 8.00 pm \n" ); document.write( " |