document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=799208>Question 799208</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Shayna left home and traveled toward the ferry office at an average speed of 40 mph. Sometime later Mary left traveling in the same direction but at an average speed of 50 mph. After traveling for four hours Mary caught up with Shayna. Find the number of hours Shayna traveled before Mary caught up. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482553 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When Mary catches up both have traveled same distance from starting point\r<BR>\n" );
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document.write( "Let Shayna travel t hours before Mary starts\r<BR>\n" );
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document.write( "Shayna speed = 40 mph\r<BR>\n" );
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document.write( "distance = 40*(t+4)\r<BR>\n" );
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document.write( "Mary distance = 50 *40\r<BR>\n" );
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document.write( "40(t+4)=200\r<BR>\n" );
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document.write( "40t+160=200<BR>\n" );
document.write( "40t=40\r<BR>\n" );
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document.write( "t=1\r<BR>\n" );
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document.write( "Shayna traveled 1 hour before Mary started\r<BR>\n" );
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document.write( " </SPAN>\n" );
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