document.write( "Question 799078: tan(sin^-1 3/4-cox^-1 1/7) \n" ); document.write( "
Algebra.Com's Answer #482514 by DrBeeee(684) ![]() You can put this solution on YOUR website! My solution may not be elegant, but I think it's right. \n" ); document.write( "Given expression \n" ); document.write( "(1) tan(arcsin(3/4) - arccos(1/7)) \n" ); document.write( "Let \n" ); document.write( "(2) a = arcsin(3/4), then \n" ); document.write( "(3) sin(a) = 3/4 and using \n" ); document.write( "(4) \n" ); document.write( "(5) \n" ); document.write( "(6) \n" ); document.write( "Now let \n" ); document.write( "(7) b = arccos(1/7), then \n" ); document.write( "(8) cos(b) = 1/7 and using \n" ); document.write( "(9) \n" ); document.write( "(10) \n" ); document.write( "(11) \n" ); document.write( "(12) \n" ); document.write( "Now a biggy! \n" ); document.write( "Use the following identities \n" ); document.write( "(13) \n" ); document.write( "(14) sin(a-b) = sin(a)cos(b) - cos(a)sin(b) \n" ); document.write( "(15) cos(a-b) = cos(a)cos(b) + sin(a)sin(b) \n" ); document.write( "There may be a more direct way to get (13), but I dont have an extensive table of trig identities in my brain. These are the only ones I remember. \n" ); document.write( "Anyway substitute (3), (6), (8), and (12) into (14) and (15) to get \n" ); document.write( "(16) \n" ); document.write( "(17) \n" ); document.write( "Now put (16) and (17) into (13) to get the solution to the problem. Note that all four terms have the common denominator, 28. Since it is in a ratio, it cancels out to give us \n" ); document.write( "(18) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |