document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=799090>Question 799090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If angle A is 3 times its supplement, angle B, what are the measurements of the angles?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482495 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If angle A is 3 times its supplement, angle B, <BR>\n" );
document.write( "what are the measurements of the angles?<BR>\n" );
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document.write( "Angle:: A = x<BR>\n" );
document.write( "supplement:: B = 180-x<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "A = 3B<BR>\n" );
document.write( "x = 3*180-x)<BR>\n" );
document.write( "x = 540 - 3x<BR>\n" );
document.write( "4x = 540<BR>\n" );
document.write( "x = 135 degrees (angle A)<BR>\n" );
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document.write( "180-x = 180-135 = 45 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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