document.write( "Question 799062: I'm having trouble in my stats class. Could anyone help me with the following question? The probability that a student is taking an English course is 0.60, that a student is taking a chemistry class is 0.30, and that a student is taking both English and chemistry is 0.12.
\n" ); document.write( "1. find the probability that a student selected at random is taking either English or chemistry
\n" ); document.write( "2. find the probability that a student selected at random is not taking English.
\n" ); document.write( "3. find the probability that a student is taking English, given that the student is taking chemistry.
\n" ); document.write( "4. are the events \"taking English\" and 'taking chemistry\" independent events? explain why?
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Algebra.Com's Answer #482489 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Use a Venn diagram. Universe is all students. Two circles, one for English, one for Chemistry. Overlap is worth 12%, English but NOT Chem is then 60% - 12% = 48%. Chem but NOT English is 30% - 12 % = 18%. Either English or Chem (or both) is 48 + 12 + 18 = 78%. Prob Eng given Chem is 12%...if Eng given Chem then must be both. Independent. The fact that a student is taking one or the other tells you nothing about whether or not they are taking the other. Contrast this with a situation where English was a pre-requisite for taking Chem -- then the probability of taking Chem would be dependent on taking or having taken English.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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