document.write( "Question 799062: I'm having trouble in my stats class. Could anyone help me with the following question? The probability that a student is taking an English course is 0.60, that a student is taking a chemistry class is 0.30, and that a student is taking both English and chemistry is 0.12.
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document.write( "1. find the probability that a student selected at random is taking either English or chemistry
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document.write( "2. find the probability that a student selected at random is not taking English.
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document.write( "3. find the probability that a student is taking English, given that the student is taking chemistry.
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document.write( "4. are the events \"taking English\" and 'taking chemistry\" independent events? explain why? \n" );
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Algebra.Com's Answer #482482 by Finavon(81) ![]() You can put this solution on YOUR website! p(E) = 0.6 \n" ); document.write( "p(C) = 0.3 \n" ); document.write( "p(E&C) = 0.12\r \n" ); document.write( "\n" ); document.write( "a) p(EorC) = 0.6+0.3 = 0.9 \n" ); document.write( "b) p(notE) = 1-0.6 = 0.4 \n" ); document.write( "c) p(C)*p(E') = p(E&C) \n" ); document.write( "p{E') = \n" ); document.write( "d) not independent. \n" ); document.write( "p(E') < p(E) and p(E&C) < p(E)*p(C) = 0.18 \n" ); document.write( " |