document.write( "Question 798920: Find 4 consecutive integers such that the sum of the first three exceeds the fourth by 18 \n" ); document.write( "

Algebra.Com's Answer #482414 by Stitch(470) $\"\"$ $\"About$

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$\"X+%2B+%28X%2B1%29+%2B+%28X%2B2%29+=+%28X%2B3%29+%2B+18\"$
\n" ); document.write( "Combine like terms
\n" ); document.write( " $\"3X+%2B+3+=+X+%2B+21\"$
\n" ); document.write( "Subtract X form both sides.
\n" ); document.write( " $\"2X+%2B+3+=+21\"$
\n" ); document.write( "Subtract 3 from both sides.
\n" ); document.write( " $\"2X+=+18\"$
\n" ); document.write( "Divide both sides by 2.
\n" ); document.write( " $\"highlight%28X+=+9%29\"$
\n" ); document.write( "The four consecutive integers are: 9, 10, 11 & 12 \n" ); document.write( "

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