document.write( "Question 798904: I need to find an equation that passes through (4,-2) and is perpendicular to x=5/4y-2. I know that I need to first set the equation equal to zero so that I can find the slope. To get rid of the fraction do I multiply everything by 4? \n" ); document.write( "
Algebra.Com's Answer #482396 by stanbon(75887)\"\" \"About 
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I need to find an equation that passes through (4,-2) and is perpendicular to x=5/4y-2. I know that I need to first set the equation equal to zero so that I can find the slope. To get rid of the fraction do I multiply everything by 4?
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\n" ); document.write( "x=(5/4)y-2
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\n" ); document.write( "(5/4)y = x+2
\n" ); document.write( "y = (4/5)x + (4/5)2
\n" ); document.write( "-----
\n" ); document.write( "y = (4/5)x + (8/5)
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\n" ); document.write( "slope of given line = 4/5
\n" ); document.write( "-----
\n" ); document.write( "slope of perpendicular line = -5/4
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\n" ); document.write( "Form: y = mx + b
\n" ); document.write( "Solve for b using m = -5/4, x = 4, y = -2
\n" ); document.write( "-2 = (-5/4)*(4) + b
\n" ); document.write( "b = 3
\n" ); document.write( "-----
\n" ); document.write( "Equation:
\n" ); document.write( "y = (-5/4)x + 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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