document.write( "Question 798780: plleae help me for this equation A certain rectangle's length is 3 feet longer than its width. If the area of the
\n" ); document.write( "rectangle is 54 square feet, find its dimensions \n" ); document.write( "
Algebra.Com's Answer #482363 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = the width
\n" ); document.write( "\"+x+%2B+3+\" = the length
\n" ); document.write( "\"+x%2A%28+x%2B+3+%29+=+54+\"
\n" ); document.write( "\"+x%5E2+%2B+3x+=+54+\"
\n" ); document.write( "You can solve this by completing the square
\n" ); document.write( "\"+x%5E2+%2B+3x+%2B+%283%2F2+%29%5E2+=+54+%2B+%283%2F2%29%5E2+\"
\n" ); document.write( "\"+x%5E2+%2B+3x+%2B+9%2F4++=++216%2F4+%2B+9%2F4\"
\n" ); document.write( "\"+x%5E2+%2B+3x+%2B+9%2F4+=+225%2F4+\"
\n" ); document.write( "\"+%28+x+%2B+3%2F2+%29%5E2+=+%28+15%2F2+%29%5E2+\"
\n" ); document.write( "\"+x+%2B+3%2F2+=+15%2F2+\"
\n" ); document.write( "\"+x+=+15%2F2+-+3%2F2+\"
\n" ); document.write( "\"+x+=+12%2F2+\"
\n" ); document.write( "\"+x+=+6+\"
\n" ); document.write( "and
\n" ); document.write( "\"+x+%2B+3+=+9+\"
\n" ); document.write( "The dimensions are 6' x 9'
\n" ); document.write( "check:
\n" ); document.write( "\"+x+=+6+\"
\n" ); document.write( "\"+x+-+6+=+0+\"
\n" ); document.write( "also, there is a negative square root in the answer, too
\n" ); document.write( "\"+x+%2B+3%2F2+=+-15%2F2+\"
\n" ); document.write( "\"+x+=+-18%2F2+\"
\n" ); document.write( "\"+x+=+-9+\"
\n" ); document.write( "\"+x+%2B+9+=+0+\"
\n" ); document.write( "So, the factors are:
\n" ); document.write( "\"+%28+x+-+6+%29%2A%28+x+%2B+9+%29+=+0+\"
\n" ); document.write( "\"+x%5E2+-+6x+%2B+9x+-+54+=+0+\"
\n" ); document.write( "\"+x%5E2+%2B+3x+=+54+\"
\n" ); document.write( "\"+x%2A%28+x+%2B+3+%29+=+54+\"
\n" ); document.write( "This is the original equation
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