document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=798638>Question 798638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels 12 miles per hour slower than the westbound train. If the two trains are  450 miles apart after 3  hours, what is the rate of the eastbound train? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482325 by </B><A HREF=/tutors/aboutme.mpl?userid=Finavon><B>Finavon(81)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Finavon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Constant speeds<BR>\n" );
document.write( "In each hour 450/3 miles travelled = 150<BR>\n" );
document.write( "12 miles for faster train leaves 138 for both<BR>\n" );
document.write( "/2. 69mph for slower (east); (+12) 81 mph for faster (west)\r<BR>\n" );
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document.write( "Same by formula 450=3e + 3(e+12) = 6e + 36<BR>\n" );
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document.write( "East=69; west=81 </SPAN>\n" );
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