document.write( "Question 798620: 3) The profit function for Wannamaker Trophies is , where f represents the design fee for a customer’s awards and m represents the monthly office rent. Also, P represents the monthly profit in dollars of the small business where x is the number of awards designed in that month.
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document.write( "a) If $80 is charged for a design fee, and the monthly studio rent is $1,600; write an equation for the profit, P, in terms of x.
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document.write( "b) How much is the profit when 50 award designs are sold in a month? Answer:
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document.write( "c) How many award designs must be sold in order to maximize the profit? Show your work algebraically.
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document.write( "d) What is the maximum profit? \n" );
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Algebra.Com's Answer #482319 by Finavon(81)![]() ![]() ![]() You can put this solution on YOUR website! a) \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b) x=50 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c) \n" ); document.write( "Graph function takes 3 pairs of numbers before the equation. \n" ); document.write( "First pair define the size of the image on the screen (width then height). \n" ); document.write( "Set this to see the graph on the screen. \n" ); document.write( "Second pair are the range of values on the x axis (min then max) \n" ); document.write( "Third pair are the range of values on the y axis (min then max) \n" ); document.write( "You can calculate some vaues, but I just set these wide to see the function. Using (-1000, 1000) for both: \n" ); document.write( " \n" ); document.write( "Inspecting the result shows that the region of interest, (in this case the values where the maximum value of y occurs) lies at higher values of y (try -500,5000). The x values can be narrowed down (try -100,400). \n" ); document.write( " \n" ); document.write( "Further adjustment (to -50,200,-300,2700) produces \n" ); document.write( " \n" ); document.write( "Inspecting this shows the max lies around 100 sales \n" ); document.write( "d) \n" ); document.write( "Max Profit @ x=100 sales \n" ); document.write( "P=-4000+8000-1600=$2400 \n" ); document.write( "That sale brought in $80 and cost 199/2.5 =$79.60 \n" ); document.write( "Next sale brings in $80 but costs 201/2.5=$80.40 \n" ); document.write( " \n" ); document.write( " |