document.write( "Question 798617: Ray is now 18 years old. His mother, Kay is now 46 years old.\r
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document.write( "a)write an expression for each person's age \"x\" years from now.
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document.write( " b) Write an equation stating that Kay is twice as old as Ray. Then solve it to find out when Kay is twice as old.
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document.write( "c) When is Kay three times as old as Ray?
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document.write( "d) write an equation stating that Ray is exactly as old as Kay. Solve it. When is this true?
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document.write( "e) write an equation stating that Ray's age is 28 years less than Kay's age. When will this be true? \n" );
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Algebra.Com's Answer #482317 by Finavon(81)![]() ![]() ![]() You can put this solution on YOUR website! a) \n" ); document.write( "Ray 18+x \n" ); document.write( "Kay 46+x\r \n" ); document.write( "\n" ); document.write( "b) \n" ); document.write( "(18+x)*2=46+x \n" ); document.write( "36+2x=46+x \n" ); document.write( "x=10 years ahead \n" ); document.write( "Ray 28; Kay 56\r \n" ); document.write( "\n" ); document.write( "c) \n" ); document.write( "(18+x)*3=46+x \n" ); document.write( "54+3x=46+x \n" ); document.write( "2x=-8 \n" ); document.write( "x=-4 \n" ); document.write( "4 years ago \n" ); document.write( "Ray 14; Kay 42\r \n" ); document.write( "\n" ); document.write( "d) \n" ); document.write( "18+x = 46+x \n" ); document.write( "Never true\r \n" ); document.write( "\n" ); document.write( "e) \n" ); document.write( "(18+x)+28=46+x \n" ); document.write( "Always true \n" ); document.write( " \n" ); document.write( " |