document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=798539>Question 798539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/2y-3/4=5/3y+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #482277 by </B><A HREF=/tutors/aboutme.mpl?userid=jackaly><B>jackaly(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jackaly><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=482277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Answer is: y=-2/3\r<BR>\n" );
document.write( "\n" );
document.write( "Here is a step by step solution:<BR>\n" );
document.write( "http://www.symbolab.com/solutions/linear_equations?query=1%2F2y-3%2F4%3D5%2F3y%2B1\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );