document.write( "Question 67828: Simplify (2x - 3) + (-x-2)\r
\n" ); document.write( "\n" ); document.write( "Please show step-by-step instructions so that my son will see how to get the answer for the future.
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Algebra.Com's Answer #48226 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Simplify (2x - 3) + (-x-2)\r
\n" ); document.write( "\n" ); document.write( "Please show step-by-step instructions so that my son will see how to get the answer for the future.\r
\n" ); document.write( "\n" ); document.write( "(2x - 3) + (-x-2) First, we'll remove the parens. For this problem, removing the parens is easy since each quantity is, in effect, multiplied by +1---And we have:\r
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\n" ); document.write( "\n" ); document.write( "2x-3-x-2
\n" ); document.write( "Note that plus one times -x=-x and
\n" ); document.write( "+1 times -2=-2\r
\n" ); document.write( "\n" ); document.write( " Now we will collect like terms but first we'll get our x's and numbers grouped together and we get:\r
\n" ); document.write( "\n" ); document.write( "2x-x-3-2\r
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\n" ); document.write( "\n" ); document.write( "x-5-----------------answer\r
\n" ); document.write( "\n" ); document.write( "Note:2x-x=x
\n" ); document.write( " -3-2=-5\r
\n" ); document.write( "\n" ); document.write( "Now, lets change the problem a little: \r
\n" ); document.write( "\n" ); document.write( "(2x-3)-3(-x-2) Now we clear parens\r
\n" ); document.write( "\n" ); document.write( "2x-3+3x+6 collect like terms;\r
\n" ); document.write( "\n" ); document.write( "5x+3\r
\n" ); document.write( "\n" ); document.write( "Note: When we clear the second set of parens, we are actually doing the following:\r
\n" ); document.write( "\n" ); document.write( "-3 times -x=+3x
\n" ); document.write( "-3 times -2=+6\r
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\n" ); document.write( "\n" ); document.write( "On these types of problems (and in math generally), it's really important that the students have a good grasp of adding, subtracting, multiplying and dividing positive and negative numbers.\r
\n" ); document.write( "\n" ); document.write( "Also, anytime you have an expression containing parens, the the terms inside the parens are being multiplied by something. As it turns out, in your problem it was +1 and, many times, when a quantity is multiplied by +1, it is not necessary to show the +1.\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps------ptaylor\r
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